InterviewSolution
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InterviewSolution
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When the size of a spherical nanoparticle decreases from 30 nm to 10 nm, the ratio surface area/volume becomesA. 1//3 of the originalB. 3 times the originalC. 1/9 of the originalD. 9 times the original |
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Answer» Correct Answer - B `("Surface area")/("Volume")=(pid^(2))/((pid^(3))/6)=6/d` `d_(1)=30 nm" "d_(2)=10 nm` `((("Surface area")/("Volume"))_(2))/((("Surface area")/("Volume"))_(1))=(6/d_(2))/(6/d_(!))=d_(1)/d_(2)=30/10=3` |
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