Saved Bookmarks
| 1. |
When the temperature of a conductor increase the ratio of its resistivity and conductivity ...... |
|
Answer» remain constant `(sigma )/(rho ) = (1)/(rho^(2))` and according to `rho = (m)/("ne"^(2) tau.) tau` decreases WITHINCREASE in TEMPERATURE Hence `rho ` INCREASES and `(1)/(rho^(2))` decreases. |
|