1.

When the temperature of a conductor increase the ratio of its resistivity and conductivity ......

Answer»

remain constant
increase
DECREASE
increase or decrease

Solution :decrease
`(sigma )/(rho ) = (1)/(rho^(2))`
and according to `rho = (m)/("ne"^(2) tau.) tau` decreases WITHINCREASE in TEMPERATURE
Hence `rho ` INCREASES and `(1)/(rho^(2))` decreases.


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