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When the tension on a wire is `4N` its length is `l_(1)`. When the tension on the wire is `4N` length is `l_(1)`. When the tension on the wire is `5N` its length is `l_(2)`. Find its natural length.A. `5l_(1) - 4l_(2)`B. `4l_(1) - 5l_(2)`C. `10l_(1) - 8l_(2)`D. `8l_(1) - 10l_(2)` |
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Answer» Correct Answer - A `(l_(1) - l)/(l_(2 - l) = (T_(1))/(T_(2))` |
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