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When the value of R in the balanced Wheatstone bridge, shown in the figure, is increased from 5 Omega to 7 Omega, the value of S has to be increased by 3 Omega in order to maintain the balance. What is the initial value of S? |
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Answer» `2.5 Omega` sinceP and Qhasconstantvalue ` thereforeP/Q =`constant`IMPLIES R/5 ` = constant Nowas perthe questiongivenin orderto maintainthe balance ` R/S = 5/S`( initially ) and ` R/S=(7 )/((S +3))`(finally ) comparingeqn(i ) and (ii) ` therefore(5)/S(S )= (7 )/((S +3)) implies 5 (S+3) = 7 S` ` implies5S+ 15 = 7S implies 7S-5S =15` `implies2S= 15 impliess=(15)/(2) = 7.5Omega ` |
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