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When three fair coins are tossed simultaneously, the probability that at least one head appears isA) 3/8B) 1/2C) 5/8D) 7/8 |
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Answer» Correct option is: D)\(\frac{7}{8}\) When three coins are tossed, then possible outcomes are {HHH, HHT, HTH, THH, HTT, THT, TTH, TTT} \(\therefore\) Total possible outcomes = n(s) = 8 Outcomes which favours the event that at least are head appears are {TTH, THT, TTH, THH, HTH, HHT, HHH} \(\therefore\) Total fabourable outcomes = n (E) = 7 \(\therefore\) Probability that at least one head appears is P = \(\frac {Total \, favourable \, outcome}{Total\, possible \, outcomes}\) = \(\frac 78\) Correct option is: D) \(\frac{7}{8}\) |
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