1.

When treated with ammoniacal cuprous chloride, which one among the following forms copper derivative

Answer»

`C_2H_6`
`C_2H_4`
`C_2H_2`
`C_6H_6`

Solution :`2NH_4OH + Cu_2Cl_2 to 2CuOH + 2NH_4Cl`
`NH_4OH+CuOH to underset"Diammine COPPER (I)hydroxide"([Cu(NH_3)_2])OH`
`2[Cu(NH_3)_2]OH + HC -=CH to underset"copperacetylide (RED ppt.)"(Cu-C-=C-Cu)+4NH_3+2H_2O`


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