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When two moles of hydrogen are heated with two moels of iodine, 2.96 moles of hydrogen iodide are formed. Calculate `K_(c)` for the reaction of formation of hydrogen iodide. |
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Answer» `H_(2)(g)+I_(2)(g) hArr 2HI(g)` At equilibrium, `2-x" "2-x" "2x` `2x=2.96` `x=(2.96)/(2)=1.48` `K_(c)=([HI]^(2))/([H_(2)][I_(2)])=((2x)^(2))/((2-1.48)(2-1.48))=(4xx(1.48)^(2))/(0.52xx0.52)=32.4` |
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