When two tuning forks (fork 1 and fork 2 ) are sounded simultaneously, 4 beats second are heard. Now some tape is attached on the prong of the fork 2. When the tuning forks are sounded again, 6 beats per second are heard. If the frequency of fork 1 is 200 Hz, then what was the original frequency of fork 2 ?

When two tuning forks (fork 1 and fork 2 ) are sounded simultaneously,

1.	When two tuning forks (fork 1 and fork 2 ) are sounded simultaneously, 4 beats second are heard. Now some tape is attached on the prong of the fork 2. When the tuning forks are sounded again, 6 beats per second are heard. If the frequency of fork 1 is 200 Hz, then what was the original frequency of fork 2 ?
Answer» 204 Hz 196 Hz 202 Hz 200 Hz Solution :`v_(2) = v_(1) pm 4= 200 pm 4 = 204 Hz or 196 Hz ` SINCE on loading the unknown FORK beat frequency INCREASES. `THEREFORE v_(2) = 196 ` Hz. so correct choice is (b) .

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