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When you have learned to integrate, calculate the change in entropy in the course of an arbitrary quasi-static process.

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Solution :Since `dS = (DeltaQ)/T and DeltaQ = dU + p dV = m/M C_(mV) dT + p dV`, it FOLLOWS that `dS = m/M C_(mV) (dT)/T + m/M R (dV)/V`. Integrating , we obtain
`S_2 - S_1 = m/M int_(T_1)^(T_2) C_(mV) (dT)/T + (dT)/T + m/M R ln (V_2)/(V_1)`
For a SMALL temperature range the ISOCHORIC heat CAPACITY may be assumed to be a constant. In this case
`S_2 - S_1= m/M (C_(mV) ln (T_2)/(T_1) + R ln (V_2)/(V_1))`


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