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When you have learned to integrate exponential functions, try to derive formulas (18.6), (18.10), and (18.12). |
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Answer» Solution :(a) `F= -kx, A= int_(x_(1))^(x_(2))F dx=-kint_(x_(1))^(x_(2))xdx= -(kx^(2))/(2)int_(x_(1))^(x_(2))=(kx_(1)^(2))/(2)-(kx_(2)^(2))/(2)`, (B) `F= (qQ)/(4piepsilon_(1)r^(2)), A= int_(r_(1))^(r_(2))Fdr= (qQ)/(4piepsilon_(1))int_(r_(1))^(r_(2))(dr)/(r^2)= -(qQ)/(4piepsilon_(0)r)|_(r_(1))^(r_(2))= (qQ)/(4piepsilon_(1)r_(1))-(qQ)/((4piepsilon_(1)r_(2)))` (C) `F= (-gammamM)/(r^(2))= ,A= int_(r_(1))^(r_(2))Fdr= -gammamMint_(r_(1))^(r_(2))(dr)/(r^(2))= (gammamM)/(r)|_(r_(1))^(r_(2))=(gammamM)/(r_(2))-(gammamM)/(r_(1))` |
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