1.

When you have learned to integrate, try to analyze the process of shorting a circuit made up of a coil and a resistor connected to a power supply with constant e.m.f., i.e. the dependence of the current on time. Assume the coil to be without a ferromagnetic core.

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Solution :Ohm.s LAW should be written in the form `epsi+epsi_(L)=iR`, where `epsi` is the emſ of the power SUPPLY and `epsi_(L)=-L (di)/(dt)` is the em.f. of self induction. Hence `delta-L (di)/(dt)=iR`
Divide by R and introduce the notation the stationary current, and `L//R=tau`, the relaxation time Me obtain the equation `I_(M)-tau (di)/(dt)= or -tau (dI)/(dt)=i-I_(M)`
Multiplying by dt, we obtain
`I-I_(M) dt, or (di)/(i-I_(M))=-(dt)/(tau)`
INTEGRATING we obtain
`int (dt)/(i-I_(M))=-1/tau int dt,"YIELDING ln "(i-I_(M))=-t/tau, ln C`.
Where C is the INTEGRATION constant. Taking antilogarithms, we obtain `(t-I_(M))/(C)=` When l= 0, the current is l= (0), so `C =I_M.` After some simple transformations we obtain `i=I_(M) (1-e^(-t//tau))`
The graph of this function is shown in 43.12, Fig. 43.6.


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