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When Zn is treated with excess of NaOH, the product obtained isA. `Zn(OH)_(2)`B. ZnOHC. `Na_(2)ZnO_(2)`D. None of the above |
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Answer» Correct Answer - C When Zn is reacted with excess of NaOH, sodium zincate is obtained. `Zn+2NaOH+2H_(2)Oto Na_(2)underset("soluble")([Zn(OH)_(4)])+H_(2)` or `An+2NaOHto Na_(2)ZnO_(2)+H_(2)` |
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