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Which algebraic identity can be used to factorise 4y2 – 4y+ 1?

Answer»

Solution : GIVEN Quadratic expression is 4y² - 4y + 1 = ( 2y )² - 2 × 2y × 1 + 1² = ( 2y - 1 )² [ By algebraic identity, a² - 2AB + b² = ( a - B )² ] = ( 2y - 1 )( 2y - 1 ) Step-by-step explanation:



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