1.

Which compound in each of the following pairs will react faster in S_(N)2 reaction with OH^(-)? 1. CH_(3)Br or CH_(3)I.

Answer»

SOLUTION :`I^(Theta)` is a better LEAVING GROUP than `Br^(Theta)`. So `CH_(3)I` reacts faster with `OH^(Theta)` ion in the `S_(N)2` PATHWAY.


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