You want to find the equation for a LINE that passes through the point (2,3) and has a slope of 1/3. First of all, remember what the equation of a line is: y = mx+b Where: m is the slope, and b is the y-intercept To start, you know what m is; it's just the slope, which you said was 1/3. So you can right away fill in the equation for a line somewhat to read: y=1/3x+b. Now, what about b, the y-intercept? To find b, THINK about what your (x,y) point means: (2,3). When x of the line is 2, y of the line must be 3. Because you said the line passes through this point, right? Now, LOOK at our line's equation so far: . b is what we want, the 1/3 is already set and x and y are just two "free variables" sitting there. We can plug anything we want in for x and y here, but we want the equation for the line that specfically passes through the the point (2,3). So, why not plug in for x the NUMBER 2 and for y the number 3? This will allow us to solve for b for the particular line that passes through the point you gave!. (2,3). y=mx+b or 3=1/3 × 2+b, or solving for b: b=3-(1/3)(2). b=7/3. The equation of the line that passes through the point (2,3) with a slope of 1/3 is y=1/3x+7/3Please MARK Me Brainliest!!!