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Which is/are correct?A. `2.303 log K=-DeltaH^(ɵ)//RT+DeltaS^(ɵ)//R`B. `DeltaG^(ɵ)=-2.303RT log K`C. `-2.303 log K=-DeltaH^(ɵ)//RT^(2)+DeltaS^(ɵ)//R`D. `2.303 log K=(1//RT)(DeltaH^(ɵ)+DeltaS^(ɵ))` |
Answer» Correct Answer - A::B `DeltaG^(ɵ)=-nRT ln K` and `2.303 log K=(-DeltaH^(ɵ))/(RT)+(DeltaS^(ɵ))/(R )` |
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