1.

Which is correct graph :

Answer»




Solution :(A)`t_(x%) prop 1/a` for SEC. order
(B)RATE`=kC_t=kC_0e^(-kt)`
`ln(-(dc)/(dt))=ln(rate)="In"kC_0-kt`
So straight line
( C) `k=Ae^(-Ea//RT)`
rate =`k.("conc.")^n =Ae^(-Ea//RT)("conc.")^n`
`ln("rate")=-(Ea)/(RT)+` constant
slope=`(-Ea)/R`
(D)`t_(0.75)/t_(0.5)`=ratio of TIME is constant with initial conc.


Discussion

No Comment Found

Related InterviewSolutions