1.

Which is larger,`(1.01)^(1000000) or 10000`?

Answer» We have
`(1.01)^(1000000)-10000`
`(1.01)^(p)-10000, " where " 1000000 =p`
`(1+0.01)^(p)-10000`
`=.^(p)C_(0) + ^(p) C_(1) xx 0.01 + .^(p)C_(2) xx (0.01)^(2)+ ...+ .^(p)C_(p) xx(0.01)^(p)-10000`
`=1+ (p xx 0.01)+[.^(p)C_(2) xx(0.01)^(2) +...+(1.01)^(p)]-10000`
`1+(1000000 xx0.01) +[.^(1000000)C_(2) xx(0.01)^(2)+...+(1.01)^(1000000)]-10000`
`1+ 10000 + " [a positive real number] "-10000`
`1+" (1 positive real number) "gt0`
Hence, `(1.01)^(1000000) gt 10000`.


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