1.

Which is the last element of the series of the actinoids ? Write the electronic configuration of this elements. Comment on the possible oxidation state of this element.

Answer»

SOLUTION :Last actinoid = Lawrencium (Z = 103)
Electronic configuration = `[RN]_(86) 5f^(14) 6^(1)7S^(2)`
POSSIBLE oxidation state = +3


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