Which law is violated in the following nuclear reaction? ._0n^1 to ._1

1.	Which law is violated in the following nuclear reaction? ._0n^1 to ._1H^1+._(-1)e^0?
Answer» Solution :The law of conservation of SPIN (angular momentum) is violeted. Each particle on right SIDE has a spin `1/2(h//2pi)` so that the RESULTANT spin on the right side is 0 or `1(h//2pi)`. And on the LEFT side, is `1/2(h//2pi)`.

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Which law is violated in the following nuclear reaction? ._0n^1 to ._1H^1+._(-1)e^0?

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