|
Answer» Hey dear ur answer
As the circuit is symmetrical so we can proceed with the concept of symmetry.
According to LAW of symmetry for circuit the resistors lying on the LINE perpendicular to AB will be dysfunctional
HENCE we have only three big wires which are in parallel.
The first wire has two resistors in series which makes the net resistance of it to be R +R = 2R
The third wire has two resistors in series which makes the net resistance of it to be R +R = 2R
The second wire has in the middle two small segments of resistance 2R and 2R in parallel so the net resistance of the small square segment will be 2R /2 = R
and the TOTAL resistance for the third wire will be = R +R+R = 3R
All these wires are in parallel so the net resistance of the combination will be:
1Req = 12R +12R +13Rso ,1Req = 3 + 3+26R = 86R = 43Rso Req = 3R4answer
If you have any more doubts just ask here on the forum and our Genius will try to help you out as soon as POSSIBLE.
|
