InterviewSolution
`CH_(3)-CH=CH-CH=CH-C_(2)H_(5)4``CH_(3)-(CH=CH)_(4)-CH_(3) 2` `H_(2)C=CH-CH=CH_(2)2^(3)+2^(1)=10` `CH_(3)(-CH=CH)_(5)-CH_(5) 2^(4)+2^(2)=20`
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