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which of the following compounds is formed when `ZnSO_(4)`is treated with liquor ammonia?A. `Zn(OH)_(2).Zn(NH_(3))_(4)SO_(4)`B. `Zn(OH)_(2).ZnSO_(4).NH_(3)`C. `[Zn(NH_(3))_(4)]SO_(4)`D. `[Zn(NH_(3))_(6)]SO_(4)` |
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Answer» Correct Answer - 3 Zinc hydroxide is formed which dissolved in the form of complex in excess of `NH_(4)OH.` `ZnSO_(4)+2NH_(4)OHrarrZn(OH)_(2)+(NH_(4))_(2)SO_(4)` `Zn(OH)_(2)+(NH_(4))_(2)SO_(4)+2NH_(4)OHrarr[Zn(NH_(3))_(4)]SO_(4)+4H_(2)O` |
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