1.

Which of the following determine shortest and longest wavelengths in hydrogen atom spectrum ?

Answer»

`(1)/(lamda)=R((1)/(1^(2))-(1)/(oo^(2))),(1)/(lamda)=R((1)/(5^(2))-(1)/(6^(2)))`
`(1)/(lamda)=R((1)/(2^(2))-(1)/(oo^(2))),(1)/(lamda)=R((1)/(5^(2))-(1)/(oo^(2)))`
`(1)/(lamda)=R((1)/(3^(2))-(1)/(4^(2))),(1)/(lamda)=R((1)/(4^(2))-(1)/(5^(2)))`
NONE of these

Solution :`(1)/(lamda)=R((1)/(1^(2))-(1)/(oo^(2))),(1)/(lamda)=R((1)/(5^(2))-(1)/(6^(2)))`
First equation of option (A) shows SERIES limit of Lyman series, which is in ultraviolet region. So `lamda` is minimum, second equation of option (A) shows first line of Pfund series, which is in INFRA RED region and shows maximum wavelength.


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