1.

Which of the following electron has minimum energy?(A) n = 3, l = 2, m = –2, s = +1/2(B) n = 4, l= 0,  m = 0, s = +1/2(C) n = 4, l= 1, m = +1, s = +1/2(D) n = 5, l = 0, m = 0, s = + 1/2

Answer»

Correct option (B) n = 4, l= 0,  m = 0, s = +1/2

Explanation:

For option (A ) electron is in 3d For option 

(B) electron is in 4s For option 

(C) electron is in 4p For option 

(D) electron is in 5s

According to A ufbau principle 4s<3d<4p<5s. Hence Answer will be n=4,l=0, m=0,s= +1/2



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