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Which of the following electron has minimum energy?(A) n = 3, l = 2, m = –2, s = +1/2(B) n = 4, l= 0, m = 0, s = +1/2(C) n = 4, l= 1, m = +1, s = +1/2(D) n = 5, l = 0, m = 0, s = + 1/2 |
Answer» Correct option (B) n = 4, l= 0, m = 0, s = +1/2 Explanation: For option (A ) electron is in 3d For option (B) electron is in 4s For option (C) electron is in 4p For option (D) electron is in 5s According to A ufbau principle 4s<3d<4p<5s. Hence Answer will be n=4,l=0, m=0,s= +1/2 |
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