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Which of the following element exhibits the strongest tendncy to from bonds. |
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Answer» `O` This `p_(pi)-d_(pi)` bonding is similar to that found in the oxides and oxoacids of P but it is contrast to the more common `p_(pi)-d_(pi)` type of double bond found in alkenes and alkynes. The size of the d orbital MUST be similar to the size of the `p` orbital to obtain effeectives `p_(pi)-d_(pi)` overlap. Since size`0`. the `d` orbital increases as we move down the group,`S` forms stronger`p_(pi)-d_(pi)` bonds relative to the bigger elements in the group.the nuclear charge is increasesd and more and more `s` and `p` electrons are added as we move across a period in the periodic Table. The size of the atom and HENCE the size of `d` orbitals decreases from`Si` and `P` and then form `S` to `Cl`. The decreases in the size of the `3d` orbitals in this series of elements leads to progressively stronger`p_(pi)-d_(pi)` bonds.THUS in the silicates there is hardly any `p_(pi)-d_(pi)` bonding. Thsu `SiO_(4)` units polymerize into an enormous variety of structures linked by `Si-O-Si sigma` bonds. In the phosphates `pi`-bonding is even stronger and has BECOME a dominant factor. Thus only a small amount of polymerization occurs. consequently, only a few polymeric compounds are known with `S-O-S` linkages. for chlorine, `p_(pi)-d_(pi)` bonding is so strong that no polymerization of oxyanions occurs. It is more appropriate to explain the `pi` bonding in terms of delocalized molecular orbitals convering several atoms, in cases where thee is more than one `pi` bond in the molecule. |
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