1.

Which of the following element exhibits the strongest tendncy to from bonds.

Answer»

`O`
`S`
`Se`
`TE`

Solution :The bond between `S` and `O`,or`Se`and`O`,are much shorter than one expects for a single bond.In some cases they may br formulated as localised double bonds.A sigma `(sigma)`bond is formed in the usual way.In addition a `pi` bond is formed by the sideways overlap ofa `p` orbital on the `O`atom with a `d` orbital on the`S` or `Se` atom,giving a `p_(pi)-d_(pi)` bonding.

This `p_(pi)-d_(pi)` bonding is similar to that found in the oxides and oxoacids of P but it is contrast to the more common `p_(pi)-d_(pi)` type of double bond found in alkenes and alkynes. The size of the d orbital MUST be similar to the size of the `p` orbital to obtain effeectives `p_(pi)-d_(pi)` overlap. Since size`0`. the `d` orbital increases as we move down the group,`S` forms stronger`p_(pi)-d_(pi)` bonds relative to the bigger elements in the group.the nuclear charge is increasesd and more and more `s` and `p` electrons are added as we move across a period in the periodic Table. The size of the atom and HENCE the size of `d` orbitals decreases from`Si` and `P` and then form `S` to `Cl`. The decreases in the size of the `3d` orbitals in this series of elements leads to progressively stronger`p_(pi)-d_(pi)` bonds.THUS in the silicates there is hardly any `p_(pi)-d_(pi)` bonding. Thsu `SiO_(4)` units polymerize into an enormous variety of structures linked by `Si-O-Si sigma` bonds. In the phosphates `pi`-bonding is even stronger and has BECOME a dominant factor. Thus only a small amount of polymerization occurs. consequently, only a few polymeric compounds are known with `S-O-S` linkages. for chlorine, `p_(pi)-d_(pi)` bonding is so strong that no polymerization of oxyanions occurs.
It is more appropriate to explain the `pi` bonding in terms of delocalized molecular orbitals convering several atoms, in cases where thee is more than one `pi` bond in the molecule.


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