1.

Which of the following have identical bond order?A. `CN^(-)`B. `O_(2)^(-)`C. `NO^(+)`D. `CN^(+)`

Answer» Correct Answer - A::C
The outer most shells of C,N and O has 4,5 and 6 electrons respectively. Thus `CN^(-)` and `NO^(+)` each has 10 outermost electrons to accommodate in the molecular orbitals. So their bond order is same. `O_(2)^(-)` has 13 and `CN^(+)` has 8 electrons in outermost orbits.


Discussion

No Comment Found

Related InterviewSolutions