InterviewSolution
`CH_3-(CH_2)_(15) N^(+)(CH_3)_3 Br^(-)` `CH_3(CH_2)_(14)CH_2 NH_2` `CH_3(CH_2)_(16) CH_2OSO_2^(-) Na^(+) ``OHC-(CH_2)_(14)-CH_2COO^(-)Na^(+)`.
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