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Which of the following is paramagnetic?A. `O_2^(-)`B. `CN^(-)`C. `NO^(+)`D. `CO`

Answer» Correct Answer - A
We work out the total number of electrons. If it is an odd number, then the molecule/ion is paramagnetic as all the electrons will not be paired. `O_2^(-)(8+8+1=17)`, `CN^(-)(6+8=14)`, `NO^(+)(7+8-1=14)`, and `CO(6+8=14)`. Therefore, `O_2^(-)` is paramagnetic due to the presence of one unpaired electron, It is also justified by its MO configuration:
`KK(sigma1s)^2(sigma^**1s)(sigma2s)^2(sigma^**2s)^2(sigma2p_z)^2(pi2p_x^2=pi2p_y^2)(pi^**2p_x^2=pi^**2p_y^1)`.
It has one unpaired `e^(-)` in antibonding `MO(pi^**2p_y)`.


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