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Which of the following is the broadcast address for a Class B network ID using the default subnetmask?(a) 172.16.10.255(b) 255.255.255.255(c) 172.16.255.255(d) 172.255.255.255I got this question in a job interview.The origin of the question is Analyzing Subnet Masks in chapter TCP/IP Protocol Suite of Computer Network

Answer»

Right option is (c) 172.16.255.255

The explanation: In this CASE, the class B network ID is 172.16.0.0. We KNOW that the default mask of a class B network is 255.255.0.0. If we OR any address in a network with the complement of the default mask (0.0.255.255), we get the broadcast address of the network. In this case, the result of OR WOULD be 172.16.255.255.



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