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Which of the following is the overall reaction of rusting?(a) 2Fe(s) → 2Fe^2+ + 4e^–(b) O2 (g)+4H^+(aq)+4e^–⟶2H2O(l)(c) 2Fe(s) + O2(g) + 4H^+(aq) → 2Fe^2+(aq) + 2H2O(l)(d) H2O ⇌ H^+ + OH^–The question was asked in class test.I would like to ask this question from Electrochemistry topic in portion Electrochemistry of Chemistry – Class 12

Answer»

Correct answer is (c) 2Fe(s) + O2(g) + 4H^+(aq) → 2Fe^2+(aq) + 2H2O(l)

EASY explanation: 2Fe(s) → 2Fe^2+ + 4e^– is the reaction that OCCURS at the anode.

O2 (g)+4H^+(aq)+4e^–⟶2H2O(l) is the reaction that occurs at the cathode.

2Fe(s) + O2(g) + 4H^+(aq) → 2Fe^2+(aq) + 2H2O(l) is the OVERALL reaction of RUSTING.



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