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Which of the following is the strongest oxidizing agent ?A. `VO_(2)^(+)`B. `Cr_(2)O_(7)^(2-)`C. `CoO_(4)^(2-)`D. `FeO_(4)^(2-)` |
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Answer» On accoumnt of the steady in the effiective nuclear charge along the series, the tendency to exhibit higher oxidation states decreases. For example, the stability of the `(+6)` state decreases as follows : `Cr_(2)O_(7)^(2-) gt MnO_(4)^(2-) gt FeO_(4)^(2-) gt CoO_(4)^(2-)` or `CrO_(4)^(2-)` Therefore, the oxidizing power increases as follows `CoO_(4)^(2-) gt gt FeO_(4)^(2-) gt MnO_(4)^(2-) gt Cr_(2)O_(7)^(2-) gt VO_(2) +` or `CrO_(4)^(2)` This also due to the increasing stability of the lower species to which they are reduced. |
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