1.

Which of the following liberate I_(2) from an iodide (NaI) ?

Answer»

`Br_(2)` and `Cl_(2)`<BR>`HNO_(2)`
`ClCH_(2) - CH_(2) Cl`
`SO_(2)`

Solution :`2KI+Br_(2) rarr 2KBr +I_(2) , NaI + HNO_(2) rarr`


Discussion

No Comment Found