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Which of the following lines coorrectly show the temperature dependence of equlibrium constant, K, for an exothermic reaction A. B and CB. C and DC. A and DD. A and B |
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Answer» Correct Answer - D `DeltaG^(@)=-RTlnK` `DeltaH^(@)-T DeltaS^(@)=-RTlnK` `-(DeltaH^(@))/(RT)+(DeltaS^(@))/(R)=lnK` Therefore ln k vs `1/T` graph will be a straight line with slope equal to `-(DeltaH^(@))/(R),` Since reactio is exothermic, therefore `DeltaH^(@)` itself will be negative resulting in positive slope. |
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