1.

Which of the following lines coorrectly show the temperature dependence of equlibrium constant, K, for an exothermic reaction A. B and CB. C and DC. A and DD. A and B

Answer» Correct Answer - D
`DeltaG^(@)=-RTlnK`
`DeltaH^(@)-T DeltaS^(@)=-RTlnK`
`-(DeltaH^(@))/(RT)+(DeltaS^(@))/(R)=lnK`
Therefore ln k vs `1/T` graph will be a straight line with slope equal to `-(DeltaH^(@))/(R),` Since reactio is exothermic, therefore `DeltaH^(@)` itself will be negative resulting in positive slope.


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