InterviewSolution
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InterviewSolution
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Which of the following pairs have identical bond order?A. `F_(2) and O_(2)^(2-)`B. `N_(2) and CO_(2)`C. `O_(2) and O_(2)^(-)`D. `N_(2) and N_(2)^(+)` |
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Answer» Correct Answer - A `F_(2) and O_(2)^(2-)` are isoelectronic . `F_(2) : (sigma1s^(2))(sigma^(**)1s^(2))(sigma2s^(2))(sigma^(**)2s^(2))(sigma2p_(z)^(2)) (sigma2p_(z)^(2)=pi2p_(y)^(2))(pi^(**)2p_(x)^(2) = pi ^(**)2p_(y)^(2))` B.O.` = 1/2 xx (10 - 8) = 1` `O_(2)^(2-) : (sigma1s^(2))(sigma^(**)1s^(2))(sigma2s^(2))(sigma^(**)2s^(2))(sigma2p_(z)^(2))(pi 2p_(x)^(2) = pi 2p_(y)^(2))(pi^(**)2p_(x)^(2) = pi^(**)2p_(y)^(2))` B.O. ` = (10-8)/2 = 1` |
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