Which of the following represents the relation between maximum power gain and maximum directivity gain of the antenna?(a) Gpmax = ηrGdmax(b) Gpmax = ηr/Gdmax(c) ηr = \(\sqrt{(G_{pmax} G_{dmax})}\)(d) ηr = \(\frac{G_{dmax}+G_{pmax}}{G_{dmax}-G_{pmax}}\)The question was asked in an international level competition.I need to ask this question from Power Gain in chapter Antenna Parameters of Antennas

Which of the following represents the relation between maximum power g

1.	Which of the following represents the relation between maximum power gain and maximum directivity gain of the antenna?(a) Gpmax = ηrGdmax(b) Gpmax = ηr/Gdmax(c) ηr = \(\sqrt{(G_{pmax} G_{dmax})}\)(d) ηr = \(\frac{G_{dmax}+G_{pmax}}{G_{dmax}-G_{pmax}}\)The question was asked in an international level competition.I need to ask this question from Power Gain in chapter Antenna Parameters of Antennas
Answer» The correct answer is (a) Gpmax = ηrGdmax The explanation is: MAXIMUM POWER GAIN is obtained when there are no ohmic LOSSES. Gpmax=\(\FRAC{U_{max}}{P_{in}/4π}\) Maximum directive gainGdmax=\(\frac{U_{max}}{P_r/4π}\, and\, \eta_r=\frac{P_r}{P_{in}}\) ∴Gpmax=ηr Gdmax

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