1.

Which of the following transitiona in hydrogen atoms emit photons of highest frequency?

Answer»

N=6 to n=2
n=2 to n=1
n=1 to n=2
n=2 to n=6

Solution :`E_(2)=(-13.6)/(2^(2))=-3.4eV`
`E_(1)=(-13.6)/(1^(2))=-13.6eV`
`hv=E_(1)-(E_(2))=-3.4 +13.6=10.2eV("MAX")`.
v is the highest i.E.` n_(2)=2+0 n=1`.


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