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InterviewSolution
| 1. |
Which of the following two routes to allyl isopropyl ether is more efficient? Explain. |
| Answer» Solution :The reaction of NaH with an alcohol (ROH) YIELDS an alkoxide (RO-). Alkoxides are generally strong BASES. If an alkoxide is reacted with a methyl or primary alkyl halide, `S_(N)2` substitution can proceed in GOOD yield. If the alkyl halide is secondary or tertiary, then elimination predominates. In this example, the second reaction (primary alkyl iodide) will give the better ratio of substitution VERSUS elimination products. | |