1.

Which of the plots of ln K vs (1/T) is/are correct?

Answer»




SOLUTION :`DELTAG^(@) = -RT ln K_(EQ) = DeltaH^(@) - T DeltaS^(@)`
ln `K_(eq) = (-DeltaH^(@))/R.1/T +(DeltaS^(@))/R`
Slope `=(-DeltaH^(@))/R, y1` in tercept `t=(DeltaS^(@))/R`


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