1.

Which of the statements regarding is incorrect.

Answer»

If both alkyl GROUPS are aromatic then peoducts are formed by `SN^(1)` mechanism
`SN2` cleavage occurs at a faster rate with HI and than HCl
If both alkyl groups are PRIMARY in polar protic solvent undergoes `SN^(2)` mechanism.
R=primary, `R^(1)` = tertiary, cleavage takes places by `S_(N)1`.

Answer :A


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