InterviewSolution
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InterviewSolution
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Which one among the following is correct if x, y, z are eliminated from, (\(\frac{bx}{y+z}\) = a, \(\frac{cy}{z+x}\) = b, \(\frac{az}{x+y}\) = c)?(a) a^2b + b^2c + c^2a + abc = 0(b) a^2b – b^2c + c^2a + abc = 0(c) a^2b + b^2c + c^2a + 2abc = 0(d) a^2b – b^2c – c^2a – abc = 0The question was asked in my homework.Query is from Application of Determinants topic in section Determinants of Mathematics – Class 12 |
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Answer» CORRECT answer is (a) a^2b + b^2c + c^2a + abc = 0 The best explanation: \(\frac{bx}{y+z}\) = abx – ay – az = 0 \(\frac{cy}{z+x}\) = bbx – cy + bz = 0 \(\frac{az}{x+y}\) = CCX + cy – az = 0 \(\BEGIN{vmatrix}b & -a & -a \\b & -c & b \\c & c & -a \end {vmatrix}\) = 0 Or, b(ca – bc) + a(-AB – bc) – a(bc + c^2) = 0 or, abc – b^2c – a^2b – abc – abc – ac^2 = 0 or, a^2b + b^2c + c^2a + abc = 0 which is the required eliminate. |
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