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Which one are correct about the solution that contains `3.42 "ppm" Al_(2)(SO_(4))_(3)` and `1.42 "ppm" Na_(2)SO_(4)`?A. `[SO_(4)^(2-)]=[Na^(+)]=[Al^(3+)]`B. `[Na^(+)]+[Al^(3+)]=[SO_(4)^(2-)]`C. `[SO_(4)^(2-)]=[Na^(+)]`D. `[Al^(3+)]=[Na^(+)]` |
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Answer» Correct Answer - B::D `3.42 "ppm"Al(SO_(4))_(3)` `-=(96xx3xx3.42)/(342)"ppm"SO_(4)^(2-)=2.88"ppm"SO_(4)^(2-)` `-=(27xx2xx3.42)/(342)"ppm"Al^(3+)=0.54"ppm"Al^(3+)` `1.42"ppm"Na_(2)SO_(4)=(96xx1.42)/(142)"ppm"SO_(4)^(2-)` `=0.96"ppm"SO_(4)^(2-)=(46xx1.42)/(142)"ppm"Na^(+)=0.46"ppm"Na^(+)` `:. [Al^(3+)]=(0.54xx10^(3))/(27xx10^(6))=2.0xx10^(-5)M` `[SO_(4)^(2-)]=((2.88+0.96)xx10^(3))/(96xx10^(6))=2.0xx10^(-5)M` `[Na^(+)]=(0.46xx10^(3))/(23xx10^(6))=2.0xx10^(-5)M` |
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