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Which point on x-axis is equidistant from (5, 9) and (- 4, 6)? |
Answer» Since the point is on x-axis, therefore coordinate of y-axis is zero. Therefore the point is P(k, 0) which is equidistance from A(5, 9) and B(- 4, 6) PA = PB \(\sqrt{(5 - k)^2 + 9^2}\) = \(\sqrt{(-4 - k)^2 + 6^2}\) On squaring both sides (5 - k)2 + 92 = (- 4 - k)2 + 62 25 - 10k + k2 + 81 = 16 - 8k + k2 + 36 25 - 2k + 81 = 16 + 36 - 25 - 81 k = 27 Therefore coordinate is (27, 0) |
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