1.

Which point on x-axis is equidistant from (5, 9) and (- 4, 6)?

Answer»

Since the point is on x-axis, therefore coordinate of y-axis is zero.

 Therefore the point is P(k, 0) which is equidistance from A(5, 9) and B(- 4, 6) 

PA = PB

\(\sqrt{(5 - k)^2 + 9^2}\) = \(\sqrt{(-4 - k)^2 + 6^2}\)

 On squaring both sides

(5 - k)2 + 92 = (- 4 - k)2 + 62

25 - 10k + k2 + 81 = 16 - 8k + k2 + 36

25 - 2k + 81 = 16 + 36 - 25 - 81

k = 27

Therefore coordinate is (27, 0)



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