1.

Which product will be obtained when "CCl"_(4) adds on R-CH=CH_(2)? Give the mechanism of formation of the products.

Answer»

Solution :`R-CH=CH_(2)+"CCl"_(4)rarrR-CHCl-CH_(2)-"CCl"_(3)+R-CHCl-CH_(2)-underset(R)underset(|)"C"H-CH_(2)-"CCl"_(3)`
Second product is formed due to COMBINATION of `R-underset(o+)"C"H-CH_(2)-"CCl"_(3)` and `R-underset(CL)underset("| ")"CH"-underset(o+)"C"H_(2)` intermediates.


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