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Which product will form when optically active form of C_4 H_9 Br is subjected to dehydrohalogenation? |
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Answer» SOLUTION :The optically active form of `C_(4)H_(9)BR " is " CH_(3)CH_(2)CHBrC_(3)`. 2-Bromobutane on dehydrohalogenation gives 2-butene according to Saytzeff rule. `CH_(3)CH_(2)CHBrCH_(3) UNDERSET(KOH)overset("alcoholic")RARR CH_(3)CH=CHCH_(3) + KBr + H_(2)O` |
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