Which will make basic buffer?A. 100 mL of 0.1 M HCl + 100 mL of 0.1 M NaOHB. 50 mL of 0.1 M NaOH + 25 mL of 0.1 M `CH_(3)COOH`C. 100 mL of 0.1 M `CH_(3)COOH` + 100 mL of 0.1 M NaOHD. 100 mL of 0.1 M HCl + 200 mL of 0.1 M `NH_(4)OH`

Which will make basic buffer?A. 100 mL of 0.1 M HCl + 100 mL of 0.1 M

1.	Which will make basic buffer?A. 100 mL of 0.1 M HCl + 100 mL of 0.1 M NaOHB. 50 mL of 0.1 M NaOH + 25 mL of 0.1 M `CH_(3)COOH`C. 100 mL of 0.1 M `CH_(3)COOH` + 100 mL of 0.1 M NaOHD. 100 mL of 0.1 M HCl + 200 mL of 0.1 M `NH_(4)OH`
Answer» Correct Answer - D Acid-base titration `underset("10 m mole")(HCl)+underset(20-10)underset("20 m mole")(Na_(4)OH)tounderset("10 m mole")(Na_(4)Cl)` HCl is limiting reagent Solution contain `underset((WB))(NH_(4)OH)&underset((SAWB))(NH_(4)Cl)` The basic buffer will form

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Which will make basic buffer?A. 100 mL of 0.1 M HCl + 100 mL of 0.1 M NaOHB. 50 mL of 0.1 M NaOH + 25 mL of 0.1 M `CH_(3)COOH`C. 100 mL of 0.1 M `CH_(3)COOH` + 100 mL of 0.1 M NaOHD. 100 mL of 0.1 M HCl + 200 mL of 0.1 M `NH_(4)OH`

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