1.

While falling, when the flower pot is at a height of 2m from the ground, what will be its kinetic energy?

Answer»

K = \(\frac{1}{2}\) mv2

u = 0, 

g = 10m/s2,

s = 4 – 2 = 2m

v2 = u2 + 2as

= 0 + 2 × 10 × 2 = 40

K = 1/2 × 15 × 40

= 300J



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