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While falling, when the flower pot is at a height of 2m from the ground, what will be its kinetic energy? |
Answer» K = \(\frac{1}{2}\) mv2 u = 0, g = 10m/s2, s = 4 – 2 = 2m v2 = u2 + 2as = 0 + 2 × 10 × 2 = 40 K = 1/2 × 15 × 40 = 300J |
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