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White coherent light (400 nm- 700 nm) is sent through the slits of a young.s double slit experiment. The separation between the slits is 0.5 mm and the screen is 50 cm away from the slits. There is a hole in the screen at a point 1 mm fromthe centre. Which wavelength will be absent in the light coming from the hole? |
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Answer» Solution :`y= (XD)/(d)= (2n-1) (lambdaD)/(2d)` `10^(-3)= (2n-1) (lambda)/(2)XX(1)/(2)xx(10^3)/(0.5)` `lambda= (2000)/(2n-1)nm` In the given WAVELENGTH range 400m and 667nm will the absent `n=1""lambda= 2000 nm""n=2"" lambda= (2000)/(3)= 667nm` `n=3""lambda= (2000)/(5)=400NM" "n=4""lambda=(2000)/(7)= 285.7nm`. 
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