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| 1. |
Why is Cr^(2+) reducing and Mn^(3+) oxidising when both have d^(4) configuration? |
| Answer» SOLUTION :`Cr^(3+) // Cr^(2+)` has a negative reduction potential or positive oxidation potential. Therefore, `Cr^(3+)` is most stable. Hence, `Cr^(2+)` can easily CHANGE to `Cr^(3+)` by the LOSS of an electron. Thus, `Cr^(2+)` acts as a strong REDUCING agent. On the other hand, `Mn^(3+)//Mn^(2+)` has large positive reduction potential. Hence, `Mn^(3+)` can be easily reduced and thus acts as a strong oxidising agent.` | |