InterviewSolution
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InterviewSolution
| 1. |
Why is `Cr^(2+)` reducing and `Mn^(3+)` oxidising when both have `d^4` configuration? |
| Answer» `Cr^(2+)` is reducing as its configuration changes from `d^(4)` to `d^(3)`, the latterhaving a half-filled `t_(2g)` level (see Unit 9) . On the other hand, the changefrom `Mn^(3+)` to `Mn^(2+)` results in the half-filled `(d^(5))` configuration which hasextra stability. | |